document.write( "Question 260233: Looking for a Proof to the theorem that given x>c, then 1/x < 1/c for any Real numbers x and c.\r
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document.write( "Thanks,
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document.write( "Gary \n" );
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Algebra.Com's Answer #191647 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! let's start out with the opposite \n" ); document.write( "1/x>1/c \n" ); document.write( "multiply both sides by x \n" ); document.write( "1>x/c \n" ); document.write( "multiply both sides by c \n" ); document.write( "c>x \n" ); document.write( " but that can't be since we are given that x>c \n" ); document.write( "so the assumption that 1/x>1/c must be wrong there fore 1/x<=1/c \n" ); document.write( "so now we have to show that 1/x can't be equal to 1/c \n" ); document.write( "1/x=1/c \n" ); document.write( "1=x/c \n" ); document.write( "c=x \n" ); document.write( "but that can't be either since we are given that x>c \n" ); document.write( "so 1/x<1/c\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |