document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=259896>Question 259896</A>: <I><SPAN STYLE=\"word-break: break-all;\"> in 2 years andy will be as old as joe is now. in 2 years joe will be 1 1/2 times as old as andy. find their ages now </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #191627 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=191627\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let joe's age be x.<BR>\n" );
document.write( "Andy's age will be x-2 now. ( because after two years andy will be joe's age.)\r<BR>\n" );
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document.write( "After two years the relation of their ages will be\r<BR>\n" );
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document.write( "x+2 = 3/2 * x ( joe is one and half times andy's age.)<BR>\n" );
document.write( "2(x+2)=3<BR>\n" );
document.write( "2x+4=3x<BR>\n" );
document.write( "3x-2x=4<BR>\n" );
document.write( "x=4 Joe's age, 4 years.\r<BR>\n" );
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document.write( "2years- Andy's age  </SPAN>\n" );
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