document.write( "Question 259994: give exact and approximate solutions to three decimal places: y^2-8y+16=1
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Algebra.Com's Answer #191626 by mananth(16946)\"\" \"About 
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y^2-8y+16=1\r
\n" ); document.write( "\n" ); document.write( "This = (y-4)^2= 1
\n" ); document.write( "Taking the square of both sides of the equation\r
\n" ); document.write( "\n" ); document.write( "we get y-4 = +1 or -1\r
\n" ); document.write( "\n" ); document.write( "therefore y =5 if it is +1 and y=3 if it is -1
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