document.write( "Question 259994: give exact and approximate solutions to three decimal places: y^2-8y+16=1
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #191626 by mananth(16946)![]() ![]() You can put this solution on YOUR website! y^2-8y+16=1\r \n" ); document.write( "\n" ); document.write( "This = (y-4)^2= 1 \n" ); document.write( "Taking the square of both sides of the equation\r \n" ); document.write( "\n" ); document.write( "we get y-4 = +1 or -1\r \n" ); document.write( "\n" ); document.write( "therefore y =5 if it is +1 and y=3 if it is -1 \n" ); document.write( " |