document.write( "Question 259864: If I have a rose, a carnation, a tulip, and a daisy; how many different ways are possible if I have a blue vase, a green vase, and a white vase?\r
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document.write( "Since a rose - carnation in a blue is the same as a carnation - rose in a blue, would this be 4!3!?\r
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document.write( "Thanks! \n" );
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Algebra.Com's Answer #191610 by rfadrogane(214)![]() ![]() You can put this solution on YOUR website! If I have a rose, a carnation, a tulip, and a daisy; how many different ways are possible if I have a blue vase, a green vase, and a white vase?\r \n" ); document.write( "\n" ); document.write( "Since a rose - carnation in a blue is the same as a carnation - rose in a blue, would this be 4!3!?\r \n" ); document.write( "\n" ); document.write( "Sol'n: \n" ); document.write( "Your sol'n is correct: \n" ); document.write( "N = 4!3! = 144 ways \n" ); document.write( " |