document.write( "Question 260125: Carol Britz plans to buy shares of two stocks. One costs $32 per share and pays dividends of $1.20 per share. The other costs $23 per share and pays dividends of $1.40 per share. She has $10,100 to spend and wants to earn dividends of $540. how many shares of each stock should she buy? \n" ); document.write( "
Algebra.Com's Answer #191585 by stanbon(75887)\"\" \"About 
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Carol Britz plans to buy shares of two stocks. One costs $32 per share and pays dividends of $1.20 per share. The other costs $23 per share and pays dividends of $1.40 per share. She has $10,100 to spend and wants to earn dividends of $540. how many shares of each stock should she buy?
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\n" ); document.write( "Cost Equation: 32x + 23y = 10,100
\n" ); document.write( "Dividend Eq::: 1.20x+1.40y = 540
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\n" ); document.write( "Multiply thru the 2nd equation by 10 to get:
\n" ); document.write( "12x + 14y = 5400
\n" ); document.write( "32x + 23y = 10,100
\n" ); document.write( "----
\n" ); document.write( "Multiply thru the 1st equation by 32
\n" ); document.write( "Multiply thru the 2nd equation by 12
\n" ); document.write( "----
\n" ); document.write( "32*12x + 32*14y = 32*5400
\n" ); document.write( "12*32x + 12*23y = 12*10,100
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\n" ); document.write( "Subtract the 2nd from the 1st equation:
\n" ); document.write( "172y = 51600
\n" ); document.write( "y = 300 (# of $23 stocks to buy)
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\n" ); document.write( "Substitute into 12x + 14y = 5400 and solve for \"x\":
\n" ); document.write( "12x + 14*300 = 5400
\n" ); document.write( "12x = 1200
\n" ); document.write( "x = 100 (# of $32 stocks to buy)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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