document.write( "Question 260136: 4x^2+4y^2= 81
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Algebra.Com's Answer #191584 by Earlsdon(6294)\"\" \"About 
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Given:
\n" ); document.write( "\"4x%5E2%2B4y%5E2+=+81\" determine the center and the radius.
\n" ); document.write( "Let's first get your equation into the standard form for a circle:
\n" ); document.write( "\"%28x-h%29%5E2%2B%28y-k%29%5E2+=+r%5E2\" where the center is at (h, k) and the radius is r.
\n" ); document.write( "\"4x%5E2%2B4y%5E2+=+81\" Divide both sides by 4.
\n" ); document.write( "\"x%5E2%2By%5E2+=+20.25\" This is now in standard form, so h = 0, k = 0, and \"r%5E2+=+20.25\" and \"r+=+4.5\"
\n" ); document.write( "The center is at (0, 0) and the radius is r = 4.5
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