document.write( "Question 260084: The width of a rectangle is 4 cm less then the length. The perimeter is 72 cm. What is the width of the rectangle? \r
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Algebra.Com's Answer #191531 by checkley77(12844) ![]() You can put this solution on YOUR website! W=L-4 \n" ); document.write( "2W+2L=72 \n" ); document.write( "2(L-4)+2L=72 \n" ); document.write( "2L-8+2L=72 \n" ); document.write( "4L=72+8 \n" ); document.write( "4L=80 \n" ); document.write( "L=80/4 \n" ); document.write( "L=20 ANS. FOR THE LENGTH. \n" ); document.write( "W=20-4=16 ANS. FOR THE WIDTH. \n" ); document.write( "PROOF: \n" ); document.write( "2*16+2*20=72 \n" ); document.write( "32+40=72 \n" ); document.write( "72=72 \n" ); document.write( " \n" ); document.write( " |