document.write( "Question 260084: The width of a rectangle is 4 cm less then the length. The perimeter is 72 cm. What is the width of the rectangle? \r
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Algebra.Com's Answer #191531 by checkley77(12844)\"\" \"About 
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W=L-4
\n" ); document.write( "2W+2L=72
\n" ); document.write( "2(L-4)+2L=72
\n" ); document.write( "2L-8+2L=72
\n" ); document.write( "4L=72+8
\n" ); document.write( "4L=80
\n" ); document.write( "L=80/4
\n" ); document.write( "L=20 ANS. FOR THE LENGTH.
\n" ); document.write( "W=20-4=16 ANS. FOR THE WIDTH.
\n" ); document.write( "PROOF:
\n" ); document.write( "2*16+2*20=72
\n" ); document.write( "32+40=72
\n" ); document.write( "72=72
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