document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=260084>Question 260084</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The width of a rectangle is 4 cm less then the length. The perimeter is 72 cm. What is the width of the rectangle? \r<BR>\n" );
document.write( "\n" );
document.write( "  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #191530 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield><B>dabanfield(803)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=191530\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The width of a rectangle is 4 cm less then the length. The perimeter is 72 cm. What is the width of the rectangle? \r<BR>\n" );
document.write( "\n" );
document.write( "Let l be the length and w the width of the rectangle. Then the perimeter = 2*l + 2*w\r<BR>\n" );
document.write( "\n" );
document.write( "We also know that w = l - 4 or equivalently l = w + 4:\r<BR>\n" );
document.write( "\n" );
document.write( "Perimeter = 72 = 2*l + 2*w.\r<BR>\n" );
document.write( "\n" );
document.write( "Substituting w + 4 for l in the equation above we have:\r<BR>\n" );
document.write( "\n" );
document.write( "72 = 2*(w+4) + 2*w\r<BR>\n" );
document.write( "\n" );
document.write( "Solve the above for w.  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );