document.write( "Question 260056: i dont know where to start or anything
\n" ); document.write( "f(x)=x+2 divided by the square root of (2x-7) g(x)=x-3\r
\n" ); document.write( "\n" ); document.write( "domain of f*g
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Algebra.Com's Answer #191501 by dabanfield(803)\"\" \"About 
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i dont know where to start or anything
\n" ); document.write( "f(x)=x+2 divided by the square root of (2x-7)and g(x)=x-3
\n" ); document.write( "Find the domain of f*g. \r
\n" ); document.write( "\n" ); document.write( "Remember that (f*g)(x) = f(x)*g(x) so\r
\n" ); document.write( "\n" ); document.write( "(f*g)(x) = [(x+2)/sqrt(2x-7)]*(x-3) = \r
\n" ); document.write( "\n" ); document.write( "[(x+2)*(x-3)/sqrt(2x-7) =\r
\n" ); document.write( "\n" ); document.write( "[x^2 - x - 6]/sqrt(2x-7)\r
\n" ); document.write( "\n" ); document.write( "The domain of this function is the set of values for x that are allowed for this expression to be defined.\r
\n" ); document.write( "\n" ); document.write( "The expression is defined except when the denominator is 0. The denominator becomes 0 when sqrt(2x-7) = 0. \r
\n" ); document.write( "\n" ); document.write( "sqrt(2x-7) = 0 if 2x-7 = 0 which is when x = 7/2.\r
\n" ); document.write( "\n" ); document.write( "The domain then is all real numbers except 7/2.
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