document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=4279>Question 4279</A>: <I><SPAN STYLE=\"word-break: break-all;\"> pat has $3.80 in nickels and dimes. If there are 51 coins in all, how many are nickles? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #1915 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=1915\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = number of nickels <BR>\n" );
document.write( " 51 - x = number of dimes\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Value of coins = number of coins times value of each coin (in cents)<BR>\n" );
document.write( "Value of nickels + Value of dimes = Total value of coins ($3.80 or 380 cents)<BR>\n" );
document.write( "5(x)   +    10(51 - x) = 380<BR>\n" );
document.write( "5x + 510 - 10x = 380<BR>\n" );
document.write( "-5x + 510 = 380<BR>\n" );
document.write( "-5x + 510 - 510 = 380 - 510<BR>\n" );
document.write( "-5x = -130<BR>\n" );
document.write( "x=26 Nickels<BR>\n" );
document.write( "51 - x = 25 Dimes\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Check:  <BR>\n" );
document.write( "Total value of nickels = $1.30<BR>\n" );
document.write( "Total value of dimes   = $2.50<BR>\n" );
document.write( "Total value of coins   = $3.80  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );