document.write( "Question 259924: Jan rollerskated to Cindy’s house against a strong headwind. She got there in 20 minutes. When she went back home, the tail wind strength was the same as before. That trip took only 8 minutes. How long would it take Jan to ride to her Cindy’s house if there was no wind? \n" ); document.write( "
Algebra.Com's Answer #191471 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! Jan rollerskated to Cindy’s house against a strong headwind. \n" ); document.write( " She got there in 20 minutes. \n" ); document.write( "When she went back home, the tail wind strength was the same as before. \n" ); document.write( " That trip took only 8 minutes. \n" ); document.write( "How long would it take Jan to ride to her Cindy’s house if there was no wind? \n" ); document.write( ": \n" ); document.write( "Let s = her speed with no wind \n" ); document.write( "Let w = the force of the wind \n" ); document.write( "then \n" ); document.write( "(s-w) = her speed against the wind \n" ); document.write( "and \n" ); document.write( "(s+w) = her speed with the wind \n" ); document.write( ": \n" ); document.write( "Choose a convenient number for the distance, 40 units \n" ); document.write( ": \n" ); document.write( "write two distance equations, time * speed = distance \n" ); document.write( "20(s-w) = 40 \n" ); document.write( "8(s+w) = 40 \n" ); document.write( "Simplify, divide the 1st equation by 20, the 2nd equation by 8 \n" ); document.write( "s - w = 2 \n" ); document.write( "s + w = 5 \n" ); document.write( "----------addition eliminates w \n" ); document.write( "2s = 7 \n" ); document.write( "s = 7/2 \n" ); document.write( "s = 3.5 \n" ); document.write( ": \n" ); document.write( "Find the time at this speed: \n" ); document.write( " \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "Prove this find the times of each situation \n" ); document.write( "When her speed is 3.5 the wind = 1.5 \n" ); document.write( ": \n" ); document.write( "against: 40/(3.5-1.5) = 20 min \n" ); document.write( "with: 40/(3.5+1.5) = 8 min \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |