document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=260026>Question 260026</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do solve step by step x^2=40?  I am suppposed to solve the equation.<BR>\n" );
document.write( "Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #191463 by </B><A HREF=/tutors/aboutme.mpl?userid=unlockmath><B>unlockmath(1688)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=unlockmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=unlockmath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=191463\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hello, <BR>\n" );
document.write( "The whole key to algebra equations is get the variable \"x\" all alone. So when we have an equation like this: x^2=40 <BR>\n" );
document.write( "The only way to get it to be \"x\" is square root both sides. When we sq rt x^2 it just becomes \"x\". But we need to sq rt the other side too so to keep it balanced.<BR>\n" );
document.write( "(sq rt)x^2=(sq rt)40<BR>\n" );
document.write( "x=6.3246 Rounded off (Also a minus 6.32)<BR>\n" );
document.write( "Now we can check this to see if it's right by putting the answer back into the original equation. <BR>\n" );
document.write( "RJ <BR>\n" );
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