document.write( "Question 260017: Strontium–90 has a half-life of 29 years. How long will it take for an initial sample of 10 mg to decay to 1 mg?\r
\n" ); document.write( "\n" ); document.write( "Do I use the formula A= Ao(1/2)^t/h
\n" ); document.write( "If yes I come up with 1=10(1/2)^t/29 which ends up to be wrong. \r
\n" ); document.write( "\n" ); document.write( "So how do I proceed? Please HELP!!!
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Algebra.Com's Answer #191460 by nerdybill(7384)\"\" \"About 
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Strontium–90 has a half-life of 29 years. How long will it take for an initial sample of 10 mg to decay to 1 mg?
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\n" ); document.write( "You can apply the general \"exponential decay\" modeled by:
\n" ); document.write( "\"A+=+Ie%5E%28kt%29\"
\n" ); document.write( "Where
\n" ); document.write( "A is the final amount
\n" ); document.write( "I is the initial amount
\n" ); document.write( "k is a constant
\n" ); document.write( "t is time
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\n" ); document.write( "\"A+=+Ie%5E%28kt%29\"
\n" ); document.write( "Plugging in your given information to first find k:
\n" ); document.write( "\"%281%2F2%2910+=+10e%5E%28k%2A29%29\"
\n" ); document.write( "\"5+=+10e%5E%28k%2A29%29\"
\n" ); document.write( "\"1%2F2+=+e%5E%28k%2A29%29\"
\n" ); document.write( "\"ln%281%2F2%29+=+29k\"
\n" ); document.write( "\"ln%281%2F2%29%2F29+=+k\"
\n" ); document.write( "\"-.0239016+=+k\"
\n" ); document.write( ".
\n" ); document.write( "Now, your actual model is:
\n" ); document.write( "\"A+=+Ie%5E%28-.0239016t%29\"
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\n" ); document.write( "And we can use to to answer your question.
\n" ); document.write( "How long will it take for an initial sample of 10 mg to decay to 1 mg?
\n" ); document.write( "\"A+=+Ie%5E%28-.0239016t%29\"
\n" ); document.write( "\"1+=+10e%5E%28-.0239016t%29\"
\n" ); document.write( "\".1+=+e%5E%28-.0239016t%29\"
\n" ); document.write( "\"ln%28.1%29+=+-.0239016t\"
\n" ); document.write( "\"ln%28.1%29%2F-.0239016+=+t\"
\n" ); document.write( "96.34 yrs = t
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