document.write( "Question 4284: If a plane flies eastward for four hours with a 60 mph tailwind and returns in five hours, what was the total distance traveled?\r
\n" ); document.write( "\n" ); document.write( "(Hint: the rate of travel eastbound is S + 60 and westbound is S - 60. S is the speed of the plane in still air.)\r
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Algebra.Com's Answer #1914 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
D = R*T\r
\n" ); document.write( "\n" ); document.write( "Let S = Rate in still air
\n" ); document.write( " S + 60 = Rate eastbound
\n" ); document.write( " S - 60 = Rate westbound
\n" ); document.write( " 4 hours = Time eastbound
\n" ); document.write( " 5 hours = Time westbound\r
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\n" ); document.write( "\n" ); document.write( "Distance traveled eastbound = Distance traveled westbound.
\n" ); document.write( "4(S + 60) = 5 (S - 60)
\n" ); document.write( "4S + 240 = 5S - 300\r
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\n" ); document.write( "\n" ); document.write( "Add -4S to each side to get all variables to the right side
\n" ); document.write( "4S - 4S + 240 = 5S - 4S - 300
\n" ); document.write( " 240 = S - 300\r
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\n" ); document.write( "\n" ); document.write( "Add 300 to each side:
\n" ); document.write( " 240 + 300 = S - 300 + 300
\n" ); document.write( " 540 MPH = S
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