document.write( "Question 4284: If a plane flies eastward for four hours with a 60 mph tailwind and returns in five hours, what was the total distance traveled?\r
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document.write( "(Hint: the rate of travel eastbound is S + 60 and westbound is S - 60. S is the speed of the plane in still air.)\r
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Algebra.Com's Answer #1914 by rapaljer(4671)![]() ![]() You can put this solution on YOUR website! D = R*T\r \n" ); document.write( "\n" ); document.write( "Let S = Rate in still air \n" ); document.write( " S + 60 = Rate eastbound \n" ); document.write( " S - 60 = Rate westbound \n" ); document.write( " 4 hours = Time eastbound \n" ); document.write( " 5 hours = Time westbound\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Distance traveled eastbound = Distance traveled westbound. \n" ); document.write( "4(S + 60) = 5 (S - 60) \n" ); document.write( "4S + 240 = 5S - 300\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Add -4S to each side to get all variables to the right side \n" ); document.write( "4S - 4S + 240 = 5S - 4S - 300 \n" ); document.write( " 240 = S - 300\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Add 300 to each side: \n" ); document.write( " 240 + 300 = S - 300 + 300 \n" ); document.write( " 540 MPH = S \n" ); document.write( " |