document.write( "Question 259926: 0.05x+0.25yh=11; 0.15x+0.05y=12 Solve by the elimination method
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Algebra.Com's Answer #191392 by richwmiller(17219)\"\" \"About 
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\n" ); document.write( "I am going to assume the h is a typo.\r
\n" ); document.write( "\n" ); document.write( "0.05x+0.25y=11
\n" ); document.write( "0.15x+0.05y=12
\n" ); document.write( "multiply first by 3
\n" ); document.write( ".15x+.75y=33
\n" ); document.write( ".15x+.05y=12
\n" ); document.write( "subtract second from first
\n" ); document.write( ".7y=21
\n" ); document.write( "y=210/7=30\r
\n" ); document.write( "\n" ); document.write( ".15x+.05(30)=12
\n" ); document.write( ".15x+1.50=12
\n" ); document.write( "15x+150=1200
\n" ); document.write( "15x=1050
\n" ); document.write( "x=1050/15
\n" ); document.write( "x=70
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