document.write( "Question 259897: solution for:
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document.write( "x+2y=7
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document.write( "x+6y=1 (ordered pairs!) \n" );
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Algebra.Com's Answer #191380 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! x + 2y = 7 \n" ); document.write( "x + 6y = 1 \n" ); document.write( "------------ subtraction eliminates x \n" ); document.write( "0 - 4y = 6 \n" ); document.write( "-4y = 6 \n" ); document.write( "y = \n" ); document.write( "y = -1.5 \n" ); document.write( ": \n" ); document.write( "Find x using x + 6y = 1 \n" ); document.write( "x + 6(-1.5) = 1 \n" ); document.write( "x - 9 = 1 \n" ); document.write( "x = 1 + 9 \n" ); document.write( "x = 10 \n" ); document.write( ": \n" ); document.write( "The ordered pair 10, -1.5 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution in the 1st equation \n" ); document.write( "x + 2y = 7 \n" ); document.write( "10 + 2(-1.5) = 7 \n" ); document.write( "10 - 3 = 7, confirms our solution \n" ); document.write( " \n" ); document.write( " |