document.write( "Question 259742: 55. The length if a rectangle is 1 more than 3 times the width. If the width is increased by 2 and the length is doubled, the new perimeter is 3 less than 5 times the original length. Find the original dimensions. \n" ); document.write( "
Algebra.Com's Answer #191336 by dabanfield(803)\"\" \"About 
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The length if a rectangle is 1 more than 3 times the width. If the width is increased by 2 and the length is doubled, the new perimeter is 3 less than 5 times the original length. Find the original dimensions.\r
\n" ); document.write( "\n" ); document.write( "Let l be the length and w the width of the rectangle:\r
\n" ); document.write( "\n" ); document.write( "1.) l = 3*w + 1 \r
\n" ); document.write( "\n" ); document.write( "perimeter = 2*l + 2*w so:
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\n" ); document.write( "2.) 2*(l*2) + 2*(w+2) = 5*l - 3\r
\n" ); document.write( "\n" ); document.write( "Substitute 3*w + 1 for l in equation 2.) and solve for w. Then calculate l = 3*w + 1\r
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