document.write( "Question 259861: Towns A and B are 300km apart. A man travels from A to B at a speed of 120km/h and a woman travels from B to A at a speed of 80km/h. The woman begins her journey 15 minutes after the man does. How far away from B will they meet? \r
\n" ); document.write( "\n" ); document.write( ": Let d = distance traveled by the woman (from town B) Then (300-d) = distance traveled by the man (from town A)
\n" ); document.write( ": Change 15 min to .25 hrs
\n" ); document.write( ": Write a time equation: Time = dist/speed
\n" ); document.write( "Man's travel time = woman's travel time + 15 min (.25 hr)
\n" ); document.write( "300-d/120 = d/80 + 1/4
\n" ); document.write( " -5d=-540 thereore d=108.
\n" ); document.write( "They will meet 108km away from B Is that correct?
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Algebra.Com's Answer #191335 by dabanfield(803)\"\" \"About 
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First we need to find the time elapsed when they meet. We can then calculate the distance traveled by either party.\r
\n" ); document.write( "\n" ); document.write( "So let t be the time elapsed when they meet. Then they meet when the two of them together have covered 300 km:\r
\n" ); document.write( "\n" ); document.write( "120*t + 80*(t-.25) = 300\r
\n" ); document.write( "\n" ); document.write( "Solve for t then calculate the man's distance from A as 120*t. \r
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