document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=32601>Question 32601</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do you work out this problem?<BR>\n" );
document.write( "{2x+10y=-2<BR>\n" );
document.write( "{6x+4y=20 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #19133 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=19133\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2X+10Y=-2<BR>\n" );
document.write( "6X+4Y=20 MULTIPLYING EQUATION 1 BY -3 WE GET<BR>\n" );
document.write( "-6X-30Y=6 NOW ADDING THESE TWO EQUATIONS WE GET<BR>\n" );
document.write( "---------<BR>\n" );
document.write( "-26Y=26 OR Y=-1 NOW SUBSTITUTING -1 FOR Y IN EITHER EQUATION WE GET<BR>\n" );
document.write( "2X+10(-1)=-2 OR 2X-10=-2 OR 2X=8 OR X=8/2 OR X=4 \r<BR>\n" );
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document.write( "PROOF SUBSTITUTING -1 FOR Y & 4 FOR X IN EQUATION TWO WE GET<BR>\n" );
document.write( "6(4)+4(-1)=20 OR 24-4=20 OR 20=20 </SPAN>\n" );
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