document.write( "Question 259853: mary is three times as old as her son .after twelvue years she is one year less than twice her sons age. what are there present ages.? \n" ); document.write( "
Algebra.Com's Answer #191326 by drk(1908)![]() ![]() ![]() You can put this solution on YOUR website! Let m = mary, and s = son. \n" ); document.write( "From above, we get \n" ); document.write( "m = 3s \n" ); document.write( "m+12 = 2(s+12) - 1 \n" ); document.write( "By substitution, we get \n" ); document.write( "3s + 12 = 2s + 23 \n" ); document.write( "s = 11 \n" ); document.write( "m = 33 \n" ); document.write( " |