document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=259846>Question 259846</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 28+12=-2(3x-8) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #191317 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=191317\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The only tricky part here is to remember that - a min is a plus<BR>\n" );
document.write( "28+12=-6x+16<BR>\n" );
document.write( "add 28+12<BR>\n" );
document.write( "subtract 16 from both sides<BR>\n" );
document.write( "40-16=-6x<BR>\n" );
document.write( "24=-6x<BR>\n" );
document.write( "-4=x<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );