document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=4285>Question 4285</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve by first eliminating the decimal numbers. \r<BR>\n" );
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document.write( "0.5x + 3.4 = 0.2x + 12.4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #1913 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=1913\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First multiply each side of the equation by 10 to clear the decimals from the problem.\r<BR>\n" );
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document.write( "5x + 34 = 2x + 124\r<BR>\n" );
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document.write( "Add -2x to each side to get all variables on the left side:<BR>\n" );
document.write( "5x - 2x + 34 = 2x - 2x + 124<BR>\n" );
document.write( "3x + 34 = 124\r<BR>\n" );
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document.write( "Subtract 34 from each side:<BR>\n" );
document.write( "3x + 34 - 34 = 124 - 34<BR>\n" );
document.write( "3x = 90\r<BR>\n" );
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document.write( "Divide each side by 3<BR>\n" );
document.write( "x = 30\r<BR>\n" );
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document.write( " </SPAN>\n" );
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