document.write( "Question 259810: Towns A and B are 300km apart. A man travels from A to B at a speed of 120km/h and a woman travels from B to A at a speed of 80km/h. The woman begins her journey 15 minutes after the man does. How far away from B will they meet?
\n" ); document.write( "Can I have the eguations of this problem?
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Algebra.Com's Answer #191290 by ankor@dixie-net.com(22740)\"\" \"About 
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Towns A and B are 300km apart.
\n" ); document.write( " A man travels from A to B at a speed of 120km/h and a woman travels from B to A at a speed of 80km/h.
\n" ); document.write( "The woman begins her journey 15 minutes after the man does.
\n" ); document.write( " How far away from B will they meet?
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\n" ); document.write( "Let d = distance traveled by the woman (from town B)
\n" ); document.write( "Then
\n" ); document.write( "(300-d) = distance traveled by the man (from town A)
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\n" ); document.write( "Change 15 min to .25 hrs
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\n" ); document.write( "Write a time equation: Time = dist/speed
\n" ); document.write( "Man's travel time = woman's travel time + 15 min (.25 hr)
\n" ); document.write( "\"%28%28300-d%29%29%2F120\" = \"d%2F80\" + .25
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\n" ); document.write( "That's the equation, if you need further help, let me know via student comment
\n" ); document.write( "I'll edit this and include the solution
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