document.write( "Question 259799: I need your assistant please help thank you in advance\r
\n" ); document.write( "\n" ); document.write( "An quiz test has a mean of 45 and standard deviation of 15. Find the corresponding z scores for:
\n" ); document.write( "- a quiz score of 29
\n" ); document.write( "- a quiz score of 25\r
\n" ); document.write( "\n" ); document.write( "Please !!!!!!!!!!!!!!!!!!!!!!!!!!!! I'm really not sure
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Algebra.Com's Answer #191274 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
My assistant is busy right now but maybe I can help... or did you mean assistance??\r
\n" ); document.write( "\n" ); document.write( "\"M=Mean=45\"
\n" ); document.write( "\"S=Sigma=15\"
\n" ); document.write( "In general,
\n" ); document.write( "\"z=%28X-M%29%2FS\", where X is your raw data.
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\n" ); document.write( "\"X=29\"
\n" ); document.write( "\"+z=%2829-45%29%2F15=+-1.067\"
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\n" ); document.write( "\"+X=25\"
\n" ); document.write( "\"+z=%2825-45%29%2F15=-1.333\"
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\n" ); document.write( "Pretty straightforward, yes?
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\n" ); document.write( "How about a quiz score of 47 and a quiz score of 40.
\n" ); document.write( "What would be the z scores for those?
\n" ); document.write( "When you reply include your answers.
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