document.write( "Question 259795: Is it possible to mix a 30% antifreeze solution with a 50% antifreeze solution and obtain a 70% antifreeze solution? Why or why not? \r
\n" ); document.write( "\n" ); document.write( "I've tried making a table with the %s, but I can't understand it.
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Algebra.Com's Answer #191262 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
No, the only mixtures you can obtain range from 30% to 50%.
\n" ); document.write( "30% means no 50% solution added to the mix.
\n" ); document.write( "50% means no 30% solution added to the mix.
\n" ); document.write( "Algebraically, let A be the # of gallons of 30% solution, B be the # of gallons of 50% solution.
\n" ); document.write( "Let's try to make 1 gallon of 70% solution.
\n" ); document.write( "\"A%2BB=1\"
\n" ); document.write( "\"30A%2B50B=70\"
\n" ); document.write( "From eq. 1,
\n" ); document.write( "\"A=1-B\"
\n" ); document.write( "\"30%281-B%29%2B50B=70\"
\n" ); document.write( "\"30-30B%2B50B=70\"
\n" ); document.write( "\"20B=40\"
\n" ); document.write( "\"B=2\"
\n" ); document.write( "Oops I need 2 gallons of B to make one gallon of 70% solution.
\n" ); document.write( "Now if you solve for A.
\n" ); document.write( "\"A=1-B=1-2=-1\"
\n" ); document.write( "Wow now I need -1 gallons, how do you do that?
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\n" ); document.write( "It's not possible, you need to increase the concentration of the solution to add least 70% or it won't work.
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