document.write( "Question 259755: solve by the elimination method 7r-4s=33 4r+7s=56\r
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document.write( "I have tried setting it up like this \r
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document.write( "7r-4s=33
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document.write( "4r+7s=56
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document.write( "3r 3s=89\r
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document.write( "I don't know if I am supposed to put a + or - between the 2 and to eliminate the variables I divide by 3 and get r,s = 29.6\r
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document.write( "this does not look right. Any help on how to solve would be appreciated. Thanks \n" );
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Algebra.Com's Answer #191208 by unlockmath(1688)![]() ![]() You can put this solution on YOUR website! Hello, \n" ); document.write( "First off we want to see if we can eliminate one of the variables. \n" ); document.write( "7r-4s=33 \n" ); document.write( "4r+7s=56 \n" ); document.write( "Let's go for getting rid of \"s\". To do this we need to multiply the first equation by 7 and the second equation by 4 so it would turn out like this: \n" ); document.write( "49r-28s=231 \n" ); document.write( "16r+28s=224 \n" ); document.write( "Now we can add both of these to be: \n" ); document.write( "65r=455 Divide each side by 65 to result in: \n" ); document.write( "r=7 \n" ); document.write( "Now we can plug 7 into either original equation to find \"s\". \n" ); document.write( "49-4s=33 Subtract 49 from both sides to be: \n" ); document.write( "-4s=-16 Now divide -4 into both sides to give us: \n" ); document.write( "s=4 \n" ); document.write( "You can check to see if this is right by plugging s=4 and r=7 into both equations. \n" ); document.write( "Make sense? \n" ); document.write( "RJ \n" ); document.write( "Check out a new book I wrote at: \n" ); document.write( "www.math-unlock.com \n" ); document.write( " |