document.write( "Question 259738: if log10x +log10y=3 then xy= \n" ); document.write( "

Algebra.Com's Answer #191192 by drk(1908) $\"\"$ $\"About$

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Using rules of logs we get
\n" ); document.write( " $\"log%2810%2Cxy%29+=+3\"$
\n" ); document.write( "rewriting using exponents we get
\n" ); document.write( " $\"10%5E3+=+xy\"$ \n" ); document.write( "

\n" );