document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=259692>Question 259692</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If m is directly proportional to x and m = 2 when x = 12, then what is the value of x when m = 2^-1?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #191151 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=191151\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If m is directly proportional to x and m = 2 when x = 12, then what is the value of x when m = 2^-1? <BR>\n" );
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document.write( "m = kx<BR>\n" );
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document.write( "Find \"k\"<BR>\n" );
document.write( "2 = k*12<BR>\n" );
document.write( "k = 1/6<BR>\n" );
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document.write( "So, m = (1/6)x<BR>\n" );
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document.write( "If m = 2^(-1) then<BR>\n" );
document.write( "2^(-1) = (1/6)x<BR>\n" );
document.write( "(1/2) = (1/6)x<BR>\n" );
document.write( "Multiply both sides by 6 to solve for \"x\":<BR>\n" );
document.write( "x = 3<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );