document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=259705>Question 259705</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The product of two positive numbers is equal to the quotient of the first number divided by the second number. If the sum of these two numbers is equal to five times their difference, find the two numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #191147 by </B><A HREF=/tutors/aboutme.mpl?userid=Branflank101><B>Branflank101(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Branflank101><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=191147\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ab = a/b<BR>\n" );
document.write( "a+b=5(a-b)\r<BR>\n" );
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document.write( "simplify ab = a/b to ab^2-a=0 Then use quadratic equation to find a:<BR>\n" );
document.write( "{formula for quadratic equation: -b +or- square root:(b^2-4ac)/2a}\r<BR>\n" );
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document.write( "a has 2 possibles: 1 or 0<BR>\n" );
document.write( "however 0 does not work for the second equation so 1 is the only possible answer for a.\r<BR>\n" );
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document.write( "simplify second equation from a+b=5(a-b) to -4a+6b=0 basically make it equal 0<BR>\n" );
document.write( "plug in 1 for a and you'll come out with the answer 2/3\r<BR>\n" );
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document.write( "so the answer for the 2 numbers are:<BR>\n" );
document.write( "a=1<BR>\n" );
document.write( "b=2/3\r<BR>\n" );
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document.write( "Check for verification and it works for both. They will both equal 1.66666667 </SPAN>\n" );
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