document.write( "Question 32626: 12c - 8d - 15rc + 10rd Please help me Factor this by Grouping \n" ); document.write( "
Algebra.Com's Answer #19112 by josmiceli(19441)\"\" \"About 
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12c - 8d - 15rc + 10rd
\n" ); document.write( "12c - 8d + (10rd - 15rc)
\n" ); document.write( "factor out 5r from the terms in parenthesis
\n" ); document.write( "12c - 8d + 5r(2d - 3c)
\n" ); document.write( "4(3c - 2d) + 5r(2d - 3c)
\n" ); document.write( "this is
\n" ); document.write( "-4(2d - 3c) + 5r(2d - 3c)
\n" ); document.write( "factor out the 2d - 3c
\n" ); document.write( "(2d - 3c)(5r - 4)
\n" ); document.write( "check this by picking some values for r,c and d
\n" ); document.write( "r = 3
\n" ); document.write( "c = 1
\n" ); document.write( "d = 7
\n" ); document.write( "12(1) - 8(7) - 15(3)(1) +10(3)(7) =
\n" ); document.write( "12 - 56 - 45 + 210 = 121
\n" ); document.write( "now the factors
\n" ); document.write( "(2(7) - 3(1))*(5(3) -4) =
\n" ); document.write( "(14 - 3)(15 - 4) =
\n" ); document.write( "11 * 11 = 121
\n" ); document.write( "OK
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