document.write( "Question 32609: A train leaves a station and travels east at 72 km/h. Three hours later a second train leaves on a parrallel track and travels east at 120 km/h. When will it overtake the first train? \n" ); document.write( "
Algebra.Com's Answer #19110 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
It usually helps to make a chart for these problems
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\n" ); document.write( "...............distance travelled.....|.rate km/hr.|..time hrs
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\n" ); document.write( "slow train........72t....................|.........72..........|......t
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\n" ); document.write( "fast train........120(t - 3).........|........120..........|......t - 3
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\n" ); document.write( "\n" ); document.write( "The time the fast train is running is 3 hours less than the slow one,
\n" ); document.write( "but the distance it travels is the same as the fast one. That's where
\n" ); document.write( "they meet. So set the distances in the chart equal to eachother.\r
\n" ); document.write( "\n" ); document.write( "72t = 120(t - 3)
\n" ); document.write( "72t = 120t - 360
\n" ); document.write( "subtract 72t from each side
\n" ); document.write( "48t = 360
\n" ); document.write( "t = 7.5
\n" ); document.write( "This is the time it takes the slow train to get to where they meet,
\n" ); document.write( "but the problem wants ti know weh the fast train will overtake it
\n" ); document.write( "It will take the fast train (t - 3) hours to overtake the slow one.
\n" ); document.write( "t = 7.5
\n" ); document.write( "(t - 3) = (7.5 - 3) = 4.5 hours
\n" ); document.write( "check the answer
\n" ); document.write( "72t = 120(t - 3)
\n" ); document.write( "72(7.5) = 120(7.5 - 3)
\n" ); document.write( "540 = 120*4.5
\n" ); document.write( "540 = 540
\n" ); document.write( "OK
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