document.write( "Question 32609: A train leaves a station and travels east at 72 km/h. Three hours later a second train leaves on a parrallel track and travels east at 120 km/h. When will it overtake the first train? \n" ); document.write( "
Algebra.Com's Answer #19110 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! It usually helps to make a chart for these problems \n" ); document.write( "* \n" ); document.write( "* \n" ); document.write( "----------------------------------------------------------------------- \n" ); document.write( "...............distance travelled.....|.rate km/hr.|..time hrs \n" ); document.write( "----------------------------------------------------------------------- \n" ); document.write( "slow train........72t....................|.........72..........|......t \n" ); document.write( "----------------------------------------------------------------------- \n" ); document.write( "fast train........120(t - 3).........|........120..........|......t - 3 \n" ); document.write( "-----------------------------------------------------------------------\r \n" ); document.write( "\n" ); document.write( "The time the fast train is running is 3 hours less than the slow one, \n" ); document.write( "but the distance it travels is the same as the fast one. That's where \n" ); document.write( "they meet. So set the distances in the chart equal to eachother.\r \n" ); document.write( "\n" ); document.write( "72t = 120(t - 3) \n" ); document.write( "72t = 120t - 360 \n" ); document.write( "subtract 72t from each side \n" ); document.write( "48t = 360 \n" ); document.write( "t = 7.5 \n" ); document.write( "This is the time it takes the slow train to get to where they meet, \n" ); document.write( "but the problem wants ti know weh the fast train will overtake it \n" ); document.write( "It will take the fast train (t - 3) hours to overtake the slow one. \n" ); document.write( "t = 7.5 \n" ); document.write( "(t - 3) = (7.5 - 3) = 4.5 hours \n" ); document.write( "check the answer \n" ); document.write( "72t = 120(t - 3) \n" ); document.write( "72(7.5) = 120(7.5 - 3) \n" ); document.write( "540 = 120*4.5 \n" ); document.write( "540 = 540 \n" ); document.write( "OK \n" ); document.write( " |