document.write( "Question 259567: Ryan left the science museum going south. Gabriel left 3 hours later riding 42 km per hour faster than ryan. After 2 hours Gabriel caught up to Ryan. Find Ryan's average speed. \n" ); document.write( "
Algebra.Com's Answer #191097 by ankor@dixie-net.com(22740)\"\" \"About 
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Ryan left the science museum going south.
\n" ); document.write( "Gabriel left 3 hours later riding 42 km per hour faster than Ryan.
\n" ); document.write( " After 2 hours Gabriel caught up to Ryan.
\n" ); document.write( " Find Ryan's average speed.
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\n" ); document.write( "Let s = Ryan's average speed
\n" ); document.write( "then
\n" ); document.write( "(s+42) = Gabriel's speed
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\n" ); document.write( "A couple useful facts
\n" ); document.write( "R's travel time = 5 hrs
\n" ); document.write( "G's travel time = 2 hrs
\n" ); document.write( "When G catch R, they will have traveled he same distance
\n" ); document.write( ":
\n" ); document.write( "Write a distance equation; dist = speed * time
\n" ); document.write( ":
\n" ); document.write( "R's dist = G's dist
\n" ); document.write( "5s = 2(s+42)
\n" ); document.write( "5s = 2s + 84
\n" ); document.write( "5s - 2s = 84
\n" ); document.write( "3s = 84
\n" ); document.write( "s = \"84%2F3\"
\n" ); document.write( "s = 28 km/hr is Ryan's speed
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\n" ); document.write( "Check solution by ensuring that they did travel the same dist
\n" ); document.write( "5(28) = 140 km
\n" ); document.write( "2(28+42) = 140 km\r
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