document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=32605>Question 32605</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the square root of (-3x-14) -x=4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #19106 by </B><A HREF=/tutors/aboutme.mpl?userid=mukhopadhyay><B>mukhopadhyay(490)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mukhopadhyay><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=19106\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Sqrt(-3x-14) - x = 4<BR>\n" );
document.write( "=> Sqrt(-3x-14) = x+4<BR>\n" );
document.write( "=> (-3x-4) = x^2 + 8x + 16 (squaring both sides)<BR>\n" );
document.write( "=> x^2 +11x + 20 = 0<BR>\n" );
document.write( "=> x = [-11 + sqrt(121-80)]/2 or x = [-11 - sqrt(121-80)]/2<BR>\n" );
document.write( "=> x = [-11 + sqrt(41)]/2 or x = [-11 - sqrt(41)]/2  </SPAN>\n" );
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