document.write( "Question 259510: Mike and Jay are brothers. Mike is 33. This is 3 times as old as Jay was when Mike was the age that Jay is today. \r
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Algebra.Com's Answer #191045 by ankor@dixie-net.com(22740)\"\" \"About 
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Mike and Jay are brothers. Mike is 33. This is 3 times as old as Jay was when Mike was the age that Jay is today.
\n" ); document.write( "How old is Jay?
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\n" ); document.write( "let j = Jay's present age
\n" ); document.write( "33-j = the difference in their ages
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\n" ); document.write( "\"This is 3 times as old as Jay was when Mike was the age that Jay is today.
\n" ); document.write( "33 = 3(j - (33-j))
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\n" ); document.write( "33 = 3(j - 33 + j)
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\n" ); document.write( "33 = 3(2j - 33)
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\n" ); document.write( "33 = 6j - 99
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\n" ); document.write( "33 + 99 = 6j
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\n" ); document.write( "132 = 6j
\n" ); document.write( "j = \"132%2F6\"
\n" ); document.write( "j = 22 yrs is Jay's present age \n" ); document.write( "
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