document.write( "Question 259544: Graph y = x^2+2x – 3 and give the vertex and
\n" ); document.write( " x and y intercepts. \n" ); document.write( "

Algebra.Com's Answer #191019 by drk(1908) $\"\"$ $\"About$

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If we complete the square on this, we get
\n" ); document.write( " y = (x+1)^2 -4
\n" ); document.write( "So, the vertex is (-1.4)
\n" ); document.write( "--
\n" ); document.write( "The x-intercepts occur when y=0, so we get
\n" ); document.write( "0 = (x+1)^2 - 4
\n" ); document.write( "adding 4 we get
\n" ); document.write( " 4 = (x+1)^2
\n" ); document.write( "taking a square root, we get
\n" ); document.write( " +-2 = x+1
\n" ); document.write( "subtracting 1, we get two answers
\n" ); document.write( "X = 1
\n" ); document.write( "and
\n" ); document.write( "x = -3
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\n" ); document.write( "The y-intercept occurs when x=0, so we get
\n" ); document.write( "y = (0+1)^2 - 4
\n" ); document.write( "y = 1^2 - 4
\n" ); document.write( "y = -3
\n" ); document.write( "--
\n" ); document.write( "the graph is
\n" ); document.write( " $\"+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+x%5E2%2B2x-3%29+\"$ \n" ); document.write( "

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