document.write( "Question 259462: a charter company will provide for a fare of $60 each for 20 or fewer passengers. for each passenger in excess of 20, the fare is decreased $2 per person for everyone what number of passengers will produce the greatest revenue for the company\r
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document.write( "OHH I REALLY NEED HELP WITH THIS!PLEASE! \n" );
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Algebra.Com's Answer #191006 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! a charter company will provide for a fare of $60 each for 20 or fewer passengers. \n" ); document.write( " for each passenger in excess of 20, the fare is decreased $2 per person for everyone what number of passengers will produce the greatest revenue for the company \n" ); document.write( ": \n" ); document.write( "Let x = no. of passengers greater than 20 \n" ); document.write( ": \n" ); document.write( "Revenue = no. of passengers * price per passenger \n" ); document.write( "r = (20+x)*(60-2x) \n" ); document.write( "FOIL \n" ); document.write( "r = 1200 - 40x + 60x - 2x^2 \n" ); document.write( "A quadratic equation \n" ); document.write( "-2x^2 + 20x + 1200 = 0 \n" ); document.write( ": \n" ); document.write( "We can find x that gives the max revenue by finding the axis of symmetry; x = -b/(2a) \n" ); document.write( "In this equation a = -2; b = 20 \n" ); document.write( "x = \n" ); document.write( "x = \n" ); document.write( "x = +5 \n" ); document.write( "; \n" ); document.write( "We can say 25 passengers will give max revenue \n" ); document.write( " |