document.write( "Question 259462: a charter company will provide for a fare of $60 each for 20 or fewer passengers. for each passenger in excess of 20, the fare is decreased $2 per person for everyone what number of passengers will produce the greatest revenue for the company\r
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\n" ); document.write( "\n" ); document.write( "OHH I REALLY NEED HELP WITH THIS!PLEASE!
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Algebra.Com's Answer #191006 by ankor@dixie-net.com(22740)\"\" \"About 
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a charter company will provide for a fare of $60 each for 20 or fewer passengers.
\n" ); document.write( " for each passenger in excess of 20, the fare is decreased $2 per person for everyone what number of passengers will produce the greatest revenue for the company
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\n" ); document.write( "Let x = no. of passengers greater than 20
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\n" ); document.write( "Revenue = no. of passengers * price per passenger
\n" ); document.write( "r = (20+x)*(60-2x)
\n" ); document.write( "FOIL
\n" ); document.write( "r = 1200 - 40x + 60x - 2x^2
\n" ); document.write( "A quadratic equation
\n" ); document.write( "-2x^2 + 20x + 1200 = 0
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\n" ); document.write( "We can find x that gives the max revenue by finding the axis of symmetry; x = -b/(2a)
\n" ); document.write( "In this equation a = -2; b = 20
\n" ); document.write( "x = \"%28-20%29%2F%282%2A-2%29\"
\n" ); document.write( "x = \"%28-20%29%2F%28-4%29\"
\n" ); document.write( "x = +5
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\n" ); document.write( "We can say 25 passengers will give max revenue
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