document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=259504>Question 259504</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is 3 cm more than the width. the area is 70cm^2. find the demensions of the rectangle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #191002 by </B><A HREF=/tutors/aboutme.mpl?userid=mathbath><B>mathbath(13)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mathbath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=191002\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the length of the rectangle be \"L\" and Width be \"B\".\r<BR>\n" );
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document.write( "From the problem we know that L is 3cm more than B. So if we put it in the form of an equation,\r<BR>\n" );
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document.write( "L = B + 3 --> (1)\r<BR>\n" );
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document.write( "The formula to calculate the area of a rectangle is.. <BR>\n" );
document.write( "A = L * B <BR>\n" );
document.write( "where A = Area of the rectangle<BR>\n" );
document.write( "L = Length of the rectangle<BR>\n" );
document.write( "B = Breadth of the rectangle <BR>\n" );
document.write( "Now from the problem we have the following values.. <BR>\n" );
document.write( "A = 70<BR>\n" );
document.write( "L = B + 3 -->(From (1) above ) <BR>\n" );
document.write( "Substituting these values in the above formula.. <BR>\n" );
document.write( "70 = (B + 3) * B<BR>\n" );
document.write( "70 = B*B + 3*B<BR>\n" );
document.write( "70 - 70 = B^2 + 3B - 70 -->(Subtracting 70 from both sides)<BR>\n" );
document.write( "0 = B^2 + 3B - 70<BR>\n" );
document.write( "0 = B*B + (10B - 7B) - (10 * 7)  --->(Since 10B - 7B = 3B and 10*7 = 70)<BR>\n" );
document.write( "0 = B(B + 10) - 7(B + 10)  --> (Taking out the common figures which are \"B\" and \"-7\" )\r<BR>\n" );
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document.write( "0 = (B + 10)(B - 7) -->(Since (B + 10) is common )\r<BR>\n" );
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document.write( "So we have the following conclusions from above,\r<BR>\n" );
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document.write( "B + 10 = 0   OR B - 7 =0<BR>\n" );
document.write( "B = -10     OR  B = 7\r<BR>\n" );
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document.write( "Now since B represents the width of the rectangle it cannot be negative. So the correct answer would be B = 7\r<BR>\n" );
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document.write( "So the breadth of the rectangle is 7cm\r<BR>\n" );
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document.write( "From (1) above we know that,<BR>\n" );
document.write( "L = B + 3\r<BR>\n" );
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document.write( "Substituting the value for B..<BR>\n" );
document.write( "L = 7 + 3<BR>\n" );
document.write( "L = 10\r<BR>\n" );
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document.write( "So the length of the rectangle is 10cm </SPAN>\n" );
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