document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=4280>Question 4280</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve by first eliminating the decimal numbers. \r<BR>\n" );
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document.write( "0.5x + 3.4 = 0.2x + 12.4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #1909 by </B><A HREF=/tutors/aboutme.mpl?userid=khwang><B>khwang(438)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=khwang><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=1909\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  If a^2x-3 * b^2x=a^6-x *b^5x prove that 3 log a =x log a/b <BR>\n" );
document.write( "  Apply log on both sides we have<BR>\n" );
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document.write( " (2x-3) log a + 2x log b = (6-x) log a + 5x log b.<BR>\n" );
document.write( "  (3x - 9) log a = 3x log b.<BR>\n" );
document.write( "  3x (log a - log b) = 9 log a,<BR>\n" );
document.write( " So,  log a/b = 3 log a.  \r<BR>\n" );
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document.write( " Note: as a good habit, you should group terms clearly as:<BR>\n" );
document.write( " a^(2x-3) * b^(2x)=a^(6-x) *b^(5x)\r<BR>\n" );
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document.write( "kENNY </SPAN>\n" );
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