document.write( "Question 32543: sqrt x =12-x \n" ); document.write( "
Algebra.Com's Answer #19084 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
sqrt x =12-x
\n" ); document.write( "square both sides to get:
\n" ); document.write( "x=144-24x+x^2
\n" ); document.write( "Simplify:
\n" ); document.write( "x^2-25x+144=0
\n" ); document.write( "Factor:
\n" ); document.write( "(x-9)(x-16)=0
\n" ); document.write( "x=9 or x=16
\n" ); document.write( "Check the answers:
\n" ); document.write( "sqrt(9)=12-9
\n" ); document.write( "3=3 OK
\n" ); document.write( "sqrt(16)=12-16
\n" ); document.write( " 4 = -4 not acceptable.
\n" ); document.write( "The only solution is x=9\r
\n" ); document.write( "\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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