document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=32587>Question 32587</A>: <I><SPAN STYLE=\"word-break: break-all;\">  I need help finding the radius and center of a circle with the following equation x squared+ y squared + 4x + 10y + 15 = 0  thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #19083 by </B><A HREF=/tutors/aboutme.mpl?userid=mukhopadhyay><B>mukhopadhyay(490)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mukhopadhyay><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=19083\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For circle (x-h)^2 + (y-k)^2 = r^2, center is (h,k) and radius is r<BR>\n" );
document.write( "x^2+y^2+4x+10y+ 15 = 0<BR>\n" );
document.write( "=> (x+2)^2 + (y+5)^2 = -15+4+25<BR>\n" );
document.write( "=> (x+2)^2 + (y+5)^2 = 14<BR>\n" );
document.write( "Center is (-2,-5) and radius is sqrt(14) </SPAN>\n" );
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