document.write( "Question 259167: Use Chebyshev’s theorem to find what percent of the values will
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document.write( "fall between 10 and 26 for a data set with mean of 18 and standard
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document.write( "deviation of 2.\r
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document.write( "Use the Empirical Rule to find what two values 99.7% of the data
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document.write( "will fall between for a data set with mean 0 and standard deviation
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document.write( "of 12. \n" );
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Algebra.Com's Answer #190827 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Use Chebyshev’s theorem to find what percent of the values will \n" ); document.write( "fall between 10 and 26 for a data set with mean of 18 and standard \n" ); document.write( "deviation of 2. \n" ); document.write( "--- \n" ); document.write( "10 is (10-18)/2 = -4 standard deviations to the left of the mean. \n" ); document.write( "28 is (26-18)/2 = +4 standard deviations to the right of the mean. \n" ); document.write( "--- \n" ); document.write( "Chebyshev says \"at least [1-(1/4)^2] = 15/16 of the data lies in \n" ); document.write( "that interval. \n" ); document.write( "15/16 = 93.75% \n" ); document.write( "---------------------------- \r \n" ); document.write( "\n" ); document.write( "Use the Empirical Rule to find what two values 99.7% of the data \n" ); document.write( "will fall between for a data set with mean 0 and standard deviation \n" ); document.write( "of 12. \n" ); document.write( "If 1-(1/k)^2 = 0.997, solve for \"k\". \n" ); document.write( "(1/k)^2 = 0.003 \n" ); document.write( "1/k = 0.05477... \n" ); document.write( "k = 18.257 (number of standard deviations to the right and to the left of zero) \n" ); document.write( "------------- \n" ); document.write( "18.257*12 = 219.09 \n" ); document.write( "---- \n" ); document.write( "99.7% of the data is between -219.09 and +219.09 \n" ); document.write( "============= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |