document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=259166>Question 259166</A>: <I><SPAN STYLE=\"word-break: break-all;\"> On a coordinate graph, what's the distance from 6,3 and 4,-6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #190813 by </B><A HREF=/tutors/aboutme.mpl?userid=CharlesG2><B>CharlesG2(834)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CharlesG2><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=190813\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> On a coordinate graph, what's the distance from 6,3 and 4,-6\r<BR>\n" );
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document.write( "distance D = sqrt((x2-x1)^2+(y2-y1)^2)\r<BR>\n" );
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document.write( "D = sqrt((4-6)^2 + (-6-3)^2)<BR>\n" );
document.write( "D = sqrt(-2^2 + -9^2)<BR>\n" );
document.write( "D = sqrt(4 + 81)<BR>\n" );
document.write( "D = sqrt(85) = 9.219544 rounded to 6 places<BR>\n" );
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