document.write( "Question 259071: A square's side is increased by 10 yards, which corresponds to an increase in the area by 400 square yards. How many yards is the side of the initial square? \n" ); document.write( "
Algebra.Com's Answer #190774 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A square's side is increased by 10 yards, which corresponds to an increase in the area by 400 square yards. \n" ); document.write( "How many yards is the side of the initial square? \n" ); document.write( ": \n" ); document.write( "Let x = side of the original square \n" ); document.write( "then \n" ); document.write( "(x+10) = side of the larger square \n" ); document.write( ": \n" ); document.write( "Large area - small area = 400 sq/yd \n" ); document.write( "(x+10)^2 - x^2 = 400 \n" ); document.write( "FOIL \n" ); document.write( "x^2 + 20x + 100 - x^2 = 400 \n" ); document.write( "20x = 400 - 100 \n" ); document.write( "20x = 300 \n" ); document.write( "x = \n" ); document.write( "x = 15 yds is the original square \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "Check it: \n" ); document.write( "25^2 - 15^2 = \n" ); document.write( "625 - 225 = 400 \n" ); document.write( " |