document.write( "Question 259080: Can someone help with this please\r
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document.write( "Solve by completing the square.\r
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document.write( "m squared - (25 over 2)m = 5 over 2\r
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document.write( "The solutions are ?\r
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document.write( "(hint Use redicalsas needed. Use a comma to separate answers.)\r
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document.write( "THank you for your help \n" );
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Algebra.Com's Answer #190763 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! \"Use redicalsas needed.\" \n" ); document.write( "I am not sure I know how! It has been a long time since I used any redicalsas. \n" ); document.write( "Needed or not! lol.\r \n" ); document.write( "\n" ); document.write( " Use a comma to separate answers. \n" ); document.write( "How generous they are with commas today! \n" ); document.write( "m^2-25m/2=5/2\r \n" ); document.write( "\n" ); document.write( "to complete the square we take 1/2 of the coefficient of m and and square it. \n" ); document.write( "(25/4)^2 and add it to both sides. \n" ); document.write( "m^2-25m/2+625/16=40/16+625/16=665/16 \n" ); document.write( "now we take the square root of both sides \n" ); document.write( "(m-25/4)^2=sqrt(665/16) \n" ); document.write( "m=25/4+\- sqrt(665/16) \n" ); document.write( "m=25/4+ sqrt(665/16) \n" ); document.write( "m=25/4- sqrt(665/16)\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "and \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |