document.write( "Question 258710: Wilma drove at an average speed of 35 mph from her home in City A to visit her sister in City B.
\n" ); document.write( "She stayed in City B 20 hours, and on the trip back averaged 55 mph. She returned home 50 hours after leaving.
\n" ); document.write( "We have to determine how many miles x is it from City A to City B.
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Algebra.Com's Answer #190752 by ankor@dixie-net.com(22740)\"\" \"About 
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Wilma drove at an average speed of 35 mph from her home in City A to visit her sister in City B.
\n" ); document.write( "She stayed in City B 20 hours, and on the trip back averaged 55 mph. She returned home 50 hours after leaving.
\n" ); document.write( "We have to determine how many miles x is it from City A to City B
\n" ); document.write( ":
\n" ); document.write( "Obviously, we are only interested in her actual travel time
\n" ); document.write( "50 - 20 = 30 hrs total travel time
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\n" ); document.write( "x = the miles between city A and B
\n" ); document.write( ":
\n" ); document.write( "Write a time equation; time = dist/speed
\n" ); document.write( "Time there + time back = 30 hrs
\n" ); document.write( "\"x%2F35\" + \"x%2F55\" = 30
\n" ); document.write( ":
\n" ); document.write( "Multiply by a common denominator, 385 with do the job
\n" ); document.write( "385*\"x%2F35\" + 385*\"x%2F55\" = 385(30)
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\n" ); document.write( "Cancel the denominators and you have:
\n" ); document.write( "11x + 7x = 11550
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\n" ); document.write( "18x = 11550
\n" ); document.write( "x = \"11550%2F18\"
\n" ); document.write( "x = 641\"2%2F3\" miles between cities
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\n" ); document.write( ":
\n" ); document.write( "Check this on calc; find the total time
\n" ); document.write( "641.67/35 + 641.67/55
\n" ); document.write( "18.33 + 11.67 = 30 hrs, confirms our solution
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