document.write( "Question 258710: Wilma drove at an average speed of 35 mph from her home in City A to visit her sister in City B.
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document.write( "She stayed in City B 20 hours, and on the trip back averaged 55 mph. She returned home 50 hours after leaving.
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document.write( "We have to determine how many miles x is it from City A to City B. \n" );
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Algebra.Com's Answer #190752 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Wilma drove at an average speed of 35 mph from her home in City A to visit her sister in City B. \n" ); document.write( "She stayed in City B 20 hours, and on the trip back averaged 55 mph. She returned home 50 hours after leaving. \n" ); document.write( "We have to determine how many miles x is it from City A to City B \n" ); document.write( ": \n" ); document.write( "Obviously, we are only interested in her actual travel time \n" ); document.write( "50 - 20 = 30 hrs total travel time \n" ); document.write( ": \n" ); document.write( "x = the miles between city A and B \n" ); document.write( ": \n" ); document.write( "Write a time equation; time = dist/speed \n" ); document.write( "Time there + time back = 30 hrs \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Multiply by a common denominator, 385 with do the job \n" ); document.write( "385* \n" ); document.write( "; \n" ); document.write( "Cancel the denominators and you have: \n" ); document.write( "11x + 7x = 11550 \n" ); document.write( "; \n" ); document.write( "18x = 11550 \n" ); document.write( "x = \n" ); document.write( "x = 641 \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "Check this on calc; find the total time \n" ); document.write( "641.67/35 + 641.67/55 \n" ); document.write( "18.33 + 11.67 = 30 hrs, confirms our solution \n" ); document.write( " \n" ); document.write( " |