document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=32327>Question 32327</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Unsure of how to type \"X to the third\" etc so it appears as X3\r<BR>\n" );
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document.write( "7-X..........X3+27<BR>\n" );
document.write( "___....x....________<BR>\n" );
document.write( "X+3.........X2-9X+14\r<BR>\n" );
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document.write( "7X3+189-X4-27X.......6X3+147<BR>\n" );
document.write( "______________  = ____________       Is This Correct?    Thank You Very Much!<BR>\n" );
document.write( "X3+4X2-13X+42......X4+4X2+14X\r<BR>\n" );
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document.write( "                  (That reads as 6X to the third plus 147 over<BR>\n" );
document.write( "                               X to the 4th + 4X squared + 14X) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #19075 by </B><A HREF=/tutors/aboutme.mpl?userid=mukhopadhyay><B>mukhopadhyay(490)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mukhopadhyay><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=19075\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> [(7-x)/(x+3)][(x^3+27)/(x^2-9x+14)]<BR>\n" );
document.write( "=[(7-x)/(x+3)][(x+3)(x^2-3x+9)/(x-7)(x-2)]<BR>\n" );
document.write( "=[-(x-7)/(x+3)][(x+3)(x^2-3x+9)/(x-7)(x-2)]<BR>\n" );
document.write( "= -(x^2-3x+9)/(x-2)<BR>\n" );
document.write( "Answer: -(x^2-3x+9)/(x-2)<BR>\n" );
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