document.write( "Question 32579This question is from textbook algebra for college students
\n" ); document.write( ": I am having trouble with this problem, I need to sove for x. let h(x)= 4^(2x-1)
\n" ); document.write( "h(x)=(square root of 2) sorry i'm not sure how to enter that.
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Algebra.Com's Answer #19071 by mukhopadhyay(490)\"\" \"About 
You can put this solution on YOUR website!
Solution for x will be in terms of h(x).
\n" ); document.write( "h(x)= 4^(2x-1)
\n" ); document.write( "Take log on both sides
\n" ); document.write( "log h(x) = log [4^(2x-1)]
\n" ); document.write( "=> log h(x) = (2x-1) log 4
\n" ); document.write( "=> (2x-1) = [log h(x)]/[2 log 2] .... (log 4 = log 2^2 = 2 log 2)
\n" ); document.write( "=> 2x = 1 + [log h(x)]/[2 log 2]
\n" ); document.write( "=> x = (1/2)[1 + {log h(x)/(2 log 2)}]
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