document.write( "Question 32574: In Solving Equations with Rational Expressions how do I answer this problem:
\n" ); document.write( "x/2 - 2/3 = 1/x? I figured out this: x/3-2/3 = 1/x, x-2/3 = 1/x, then I cross multiply and I would be at x^2-2x = 3 but after that I'm stuck.
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Algebra.Com's Answer #19067 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Solve:
\n" ); document.write( "\"x%2F2+-+2%2F3+=+1%2Fx\" Simplify the left side.
\n" ); document.write( "\"%283x-4%29%2F6+=+1%2Fx\" Multiply both sides by 6.
\n" ); document.write( "\"3x-4+=+6%2Fx\" Multiply both sides by x.
\n" ); document.write( "\"3x%5E2-4x+=+6\" Subtract 6 from both sides.
\n" ); document.write( "\"3x%5E2-4x-6+=+0\" Solve this using the quadratic formula:\"x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F2a\".
\n" ); document.write( "\"x+=+%28-%28-4%29%2B-sqrt%28%28-4%29%5E2-4%281%29%28-6%29%29%29%2F2%281%29\"
\n" ); document.write( "\"x+=+%284%2B-sqrt%2816%2B24%29%29%2F2\"
\n" ); document.write( "\"x+=+%284%2B-sqrt%2840%29%29%2F2\"
\n" ); document.write( "\"x+=+%284%2B-2sqrt%2810%29%29%2F2\"
\n" ); document.write( "\"x+=+2%2Bsqrt%2810%29\" or \"x+=+2-sqrt%2810%29\"
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