document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=258963>Question 258963</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a 19-inch television has a rectangular screen whose diagonal measures 19 inches. If the width of the screen is 15 inches, what is its height to the nearest inch? \r<BR>\n" );
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document.write( "Please show me how you arrived at the answer.  I would like to be able to go over this with my 14 year old son in 8th grade.  Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #190657 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=190657\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This depends on the Pythagorean theorem about right triangles.<BR>\n" );
document.write( "a and b are the legs (sides of the TV)  and c is the diagonal ( the hypotenuse)<BR>\n" );
document.write( "a^2+b^2=c^2<BR>\n" );
document.write( "where a=15 and c=19<BR>\n" );
document.write( "15^2+b^2=19^2<BR>\n" );
document.write( "225+b^2=361<BR>\n" );
document.write( "136=b^2<BR>\n" );
document.write( "11.66=c<BR>\n" );
document.write( "We are not interested in negative roots since we can't have a negative side to the TV<BR>\n" );
document.write( "11.66 is closest to 12 inches. </SPAN>\n" );
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