document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=258939>Question 258939</A>: <I><SPAN STYLE=\"word-break: break-all;\"> For the following function  f(x)=3x2-x+4 find<BR>\n" );
document.write( "f(2)<BR>\n" );
document.write( "F(2x)<BR>\n" );
document.write( "F(2x+2)\r<BR>\n" );
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document.write( " <BR>\n" );
document.write( "  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #190646 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=190646\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For the following function <BR>\n" );
document.write( "f(x)=3x^2-x+4 find<BR>\n" );
document.write( "f(2)= 3*2^2 - 2 + 4 = 12+2 = 14<BR>\n" );
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document.write( "F(2x) = 3(2x)^2 - 2x + 4 = 12x^2 -2x +4<BR>\n" );
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document.write( "F(2x+2) = 3(2x+2)^2 + 2x+2 + 4 <BR>\n" );
document.write( "= 3(4x^2+8x+4) + 2x^2 + 4<BR>\n" );
document.write( "---<BR>\n" );
document.write( "= 6x^2 + 24x + 16<BR>\n" );
document.write( "====================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. <BR>\n" );
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